Answer Posted / letskools

#include<stdio.h>
#include<conio.h>
void main()
{
int a[5];
int i, j,rem,k=0,x=1;
int num;
printf("enter any number");
scanf("%d",&num);
while(num>0)
{
rem = num % 10;
a[k] = rem * x;
x *= 10;
k++;
num /= 10;
}
for (i = k-1; i >= 0; i--)
{
printf("%d\n"a[i]);
}
getch();
}

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