A thief steals half the total no of loaves of bread plus 1/2
loaf from a bakery. A second thief steals half the remaining
no of loaves plus 1/2 loaf and so on. After the 5th thief
has stolen there are no more loaves left in the bakery. What
was the total no of loaves did the bakery have at the beginning
Answer Posted / paul
31 is the answer...
let y be the total no. of loaves
a be the remaining loaves after 1st thief
b be the remaining loaves after 2nd thief
.
.
e = 0 be the remaining loaves after 5th thief
solution:
a = y - 0.5y - 0.5
= 0.5y - 0.5
b = a - 0.5a - 0.5
= 0.5a - 0.5
c = 0.5b - 0.5
d = 0.5c - 0.5
e = 0.5d - 0.5 but e = 0,
thus,
d = 1
c = 3
b = 7
a = 15
y = 31 -> answer
Is This Answer Correct ? | 188 Yes | 8 No |
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