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what the differant between Wet Leg /Dry Leg
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Answer Posted / www.islamqa.com
They are diffrential pressure transmitter "installation
technique" used in "level measurement"
When installing diffrential pressure transmitter we attach 2
impulse lines with high & low transmitter sides, the 1
attached to low side is empty impulse line so it is "dry
leg" or it's filled with a sealing liquid with density
greater than the process liquid so it is "wet leg".
We use "dry leg" for closed pressurized tank.
We use "wet leg" for closed pressurized tank also but if we
have the probability of process liquid condensable vapor
which will give a faulty measurement.
If we have an open tank, the Tx low side is atmospheric.
Regards,
Ahmed Sabry
Control and Instrumentation Engineer
GPC - General Petroleum Company
CELL.: 00 2 0121367310
ahmedsabry.onine@gmail.com
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Q1: Consider part of a control loop, which excludes the transmitter, consisting of a process, a controller and a control valve which may be represented by two dead times of 0.5 min each and three exponential lags of 0.8 min., 1.0 min. and 1.5 min. respectively. We wish to express this system as an overall first order plus dead time (FOPLD) model ie gain, time constant and process dead time. (We will see later that this is often done, to simplify controller tuning). For this exercise, gain is considered to be 1.0. (A) If the transmitter is a flow transmitter whose behaviour can be described by a dead time of 0.2 min. and an exponential lag of 0.5 min. in terms of the overall dead time and overall first order lag how can the system behaviour be approximated ? Overall dead time = Overall time constant = (B) If the transmitter is a temperature transmitter with a temperature sensor in a protecting well whose behaviour can be described by a dead time of 0.7 min. and an exponential lag of 15 min. how can the overall system behaviour be approximated now? Overall dead time = Overall time constant =
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