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I have PS flat file with 14 records. I want to read from
4th to 9th record and want to write those 6 records (4th
record to 9th record) to another PS file (output file).
there is no key defined in the input file. I just want read
a certain Consecutive records. can any one please give me
the procedure division Coding for this. I have coded the
below coding but the READ-PARA is performing only 1 time
even though I have 14 records in my input file (i.e FILE-1):
PROCEDURE DIVISION.
A000-SECTION.
MOVE 0 TO I.
OPEN INPUT FILE-1.
IF CHECK-KEY1 > 0
DISPLAY "OPEN ERROR FOR FILE-1, CODE IS:" CHECK-KEY1
END-IF.
OPEN EXTEND NEWFILE-1
IF CHECK-KEY3 > 0
DISPLAY "OPEN ERROR FOR NEWFILE-1 COD IS" CHECK-KEY3
END-IF.
PERFORM READ-PARA THRU EXIT-PARA UNTIL EOF-REC = 'YES'.
DISPLAY " FINALLY OUT OF LOOP"
CLOSE FILE-1
CLOSE NEWFILE-1
STOP RUN.
READ-PARA.
ADD 1 TO I
READ FILE-1
AT END MOVE 'YES' TO EOF-REC
IF I > 3 AND < 10
PERFORM WRITE-PARA
ELSE
DISPLAY "NOT IN RANGE"
END-IF.
EXIT-PARA.
EXIT.
WRITE-PARA.
WRITE NEW-REC FROM FILE1-REC.
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Answer Posted / gowd
AS YOU ARE USING NORMAL PS FILE U CANT ACCESS THE RECORD
FROM THE MIDDLE. THE SEQUENTIAL FILE PROCESS IN SEQUENCE
ORDER FROM FIRST RECORD ONWARDS. U MENTIONED A KEY IN THE
PROGRAM IT DOES NOT ALLOW ANY KEY IN THE SEQUENTIAL FILE.
THROUGH COBOL U CANT ACCESS THIS. FROM JCL U CAN GET IT AS
ONE OF OUR FRIEND CODED THROUGH THE "REPRO".
| Is This Answer Correct ? | 0 Yes | 1 No |
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write a cobol logic. i have file that has 10 records .1 record go to first output file and second record goes to 2 output and etc
input 1 input2 ouput1 output2 output 3 1 re 300 1 re 200 1 re 300 3 rc 500 1 re 200 2 rr 400 1 re 300 2 rr 400 1 rc 400 3 rc 500 1 rc 400 2 rr 700 2 rr 700 5 tt 900 5 tt 900 2 inputs r in flat file and output 1 is matched records,ouptput2 is unmatched of input1,output3 is unmatched of input2! how vl u get the output files using sequential order and to check with each and every records! let me know the procedure division ?
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