How to initialize 20,000 bytes in the Assembler..
- 5 Answers
- 16740 Views
- Amdocs, IBM, I also Faced
- E-Mail Answers
Answer Posted / saurabh biswas
To initialize a 20000 byte field you have to use MVCL
instruction. Let's say VAR1 is defined as " VAR1 DS XL20000"
For using MVCL instruction you require two even-odd regiter
pair, even registers will contain the destination and
source address respectively, first odd register will
contain the destination leght and from 2nd to 4th byte of
the second odd register will contain the source length and
the first byte will contain filler(it will come into play
if destination lenghth is shorter than source). Now if we
want to initialize VAR1 with spaces we have to code like
following way:
LA R4,VAR1
LA R5,20000
XR R8,R8
XR R9,R9
ICM R9,B'1000',X'40'
MVCL R4,R8
Here source length is 0 and destination length is 20000. So
no move ment will occur and all the 20000 byte will be
filled by the filler wich is space here. So as result of
this instruction all 20000 byte will be initialized by
spaces.
| Is This Answer Correct ? | 25 Yes | 4 No |
Post New Answer View All Answers
Explain how to produce soc7 abend?
Why do we use "drop"?
What is icm instruction?
How is data passed from a calling program to an assembler called program?
how to initialize a register to 0000?
What does "using" do?
how to retrieve the instream data in sysin?
What is maximum displacement and how to cross this limit?
Ap wkur,=p5 where wkur is a label?
Explain about base register?
Explain the difference in data type "x" and "p"?
Explain the difference between various read and find statement?
How to pass the parameters from jcl to assembler program?
Explain how to access vsam file?
How are data passed from jcl parm to assembler program?
