A person X have a certain number of mangoes, he gave 1/2 of
total plus one mango to B, now he gave the 1/3 of remaining
plus one mango to C, he gave the 1/4 of remaining plus one
mango to D. Now he have no mango more, find how many mango
was at beginning?
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Answer Posted / nagicaj
Initially A has x
Now A gives B: x/2+1
So A has x/2-1 = (x-2)/2
Now A gives C: ((x-2)/2)/3+1
So A has ((x-2)/2)/3-1 = (x-8)/6
Now A gives D: ((x-8)/6)/4+1
So A has ((x-8)/6)/4-1=0
Solving the above x = 32 mangoes.
| Is This Answer Correct ? | 6 Yes | 4 No |
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