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class foo {
public:
static int func(const char*& p) const;
};
This is illegal, why?
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Answer Posted / rohit
the 2nd const used in the example is invalid because it can
be used only with member functions which have a hidden
argument called this. The 2nd const would be applied to
this.
The funct is static member function so it hasn't any this
pointer.
Actually it is not obvious what is exactly inccorect.
We can remove static keyword, then we get syntactically
correct class definition, or we can remove 2nd const and
again the class can be considered valid.
A member function can be declard as Const by considering
the fact that they contain a hidden "this pointer" to be a
pointer to a const object. However Static methods do not
have the "this pointer", and hence can't be const or
virtual.
Hence it is illegal to declare a static function as const.
The C++ language standard stipulates at section 9.4.1
that "[...] A static
member function shall not be declared const
| Is This Answer Correct ? | 0 Yes | 1 No |
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Why we not create function inside function.
the factorial of non-negative integer n is written n! and is defined as follows: n!=n*(n-1)*(n-2)........1(for values of n greater than or equal to 1 and n!=1(for n=0) Perform the following 1.write a c program that reads a non-negative integer and computes and prints its factorial. 2. write a C program that estimates the value of the mathematical constant e by using the formula: e=1+1/!+1/2!+1/3!+.... 3. write a c program the computes the value ex by using the formula ex=1+x/1!+xsquare/2!+xcube/3!+....
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