Give a fast way to multiply a number by 7
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Answer Posted / rupesh
There is a problem with
x=(x<<3)-x;
Suppose that x is stored in 8 bit format.
If x = 64, i.e. 2^6, then this won't work.
In general, if x is n-bit, and value of x > 2^(n-3), then
this won't work.
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