Min-Max
Write an algorithm that finds both the smallest and
largest numbers in a list of n numbers and with complexity
T(n) is at most about (1.5)n comparisons.
Answer Posted / srinivasan
#include<stdio.h>
#define size 10
void main()
{
int a[size]={5,3,18,7,20,0,2,1,16,13},i,j,count=0,t,max,min;
clrscr();
for(i=0;i<size;i++)
printf("%5d",a[i]);
for(i=0,j=size-1;i<j;i++,j--)
{
count++;
if(a[i]>a[j])
{
t=a[i],a[i]=a[j],a[j]=t;
}
}
printf("\n\n");
for(i=0;i<size;i++)
printf("%5d",a[i]);
printf("\n\n");
min=a[0];
for(i=1;i<size/2;i++)
{
count++;
if(a[i]<min)
min=a[i];
}
max=a[size/2];
for(j=size/2+1;j<size;j++)
{ count++;
if(a[j]>max)
max=a[j];
}
printf("%d\n%d is max,min",max,min);
printf("\n%d\n",count);
getch();
}
Is This Answer Correct ? | 10 Yes | 9 No |
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