We have 2 poles 5 m and 7 m height ropes are connected from
top of one to tthe bottem of another find the intersection
height of those poles.
Answer Posted / rohit_allinterview
Can be calculated using similarity properties of triangles.
Steps:
Step1: Treat line AB as pole1 of 5mts.
Step2: Treat line CD as pole2 of 7mts.
Step3: Let E be the intersection of AD and BC.
Step4: Drop E perpendicular to BD at F. EF=? to b calculated
Step5: Trngl EFD and Trng ABD are similar, Hence
AB/EF= BD/FD. ==> 5/EF=BD/FD
So, EF = 5*FD/BD ------> Eq.1
Similarily, considering trngl's CDB, EFB. They are similar.
Hence, CD/EF = BD/BF ===> 7/EF= BD/(BD-FD)
So, EF = 7*(BD-FD)/BD ----> Eq .2
Solve eq 1 and eq 2. i.e., Equate eq 1 and eq 2.
Hence u get 12*FD=7*BD => FD=7*BD/12 -----> Eq 3
Solve Eq 1 and Eq 3. i.e., substitute FD in Eq1.
EF=35/12= 2.916
Plz rate it if it is correct/incorrect. For any
clarification mail me at rohit_vit2020@yahoo.co.in
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