Answer Posted / senthilkumar

#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int lsum,sum,i,j,n,a[20],flag=0;
lsum=0;sum=0;
cout<<"Enter the total no. of elements:";
cin>>n;

for(i=0;i<n;i++)
cin>>a[i];

//Checking condition whether there are only negative numbers
for(i=0;i<n;i++)
{
if(a[i]>0)
flag++;
}
//for array including positive and negative numbers
if(flag>0)
{
for(i=0;i<n;i++)
{
sum+=a[i];
if(sum<0)
{
sum=0;
j++;
i=j;
}
else if(lsum<sum)
lsum=sum;
}
}
//for array having only negative numbers
else
{
lsum=a[0];
for(i=0;i<n;i++)
{
if(lsum<a[i])
lsum=a[i];
}
}
cout<<"The largest sum is:"<<lsum;
getch();
}

I need your help, i need a Turbo C code for this problem.. hope u'll help me guys.? Your program will have a 3x3 array. The user will input the sum of each row and each column. Then the user will input 3 values and store them anywhere, or any location or index, temporarily in the array. Your program will supply the remaining six (6) values and determine the exact location of each value in the array. Example: Input: Sum of row 1: 6 Sum of row 2: 15 Sum of row 3: 24 Sum of column 1: 12 Sum of column 2: 15 Sum of column 3: 18 Value 1: 3 Value 2: 5 Value 3: 6 Output: Sum of Row 1 2 3 6 4 5 6 15 7 8 9 24 Sum of Column 12 15 18 Note: Your program will not necessary sort the walues in the array Thanks..

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