Answer Posted / sunil

#include<stdio.h>
#include<conio.h>

char a[10][12]={"one","two","three","four","five","six","seven","eight","nine"};
char b[10][15]={"eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","ninteen"};
char tens[10][15]={"twenty","thirty","fourtey","fiftey","sixty","seventy","eighty","ninty"};

int check(long int num)
{
if(num>10000000)return 5;
if(num>100000)return 4;
else if(num>1000)return 1;
else if(num>100)return 2;
else if(num>10)return 3;
else

return 0;
}

void prnt(long int num,char *s)
{ int n;
if(num<10)
{
printf(" %s %s",a[num-1],s);

}
else if(num>10 && num<20)
{
printf(" %s %s",b[(num-10)-1],s);
}
else if(num>20)
{
printf(" %s ",tens[(num-20)/10]);

n=num%10;
printf(" %s %s",a[n-1],s);
}

}

void main()
{
long int num,n;
int ch=1;

printf("enter no\n");
scanf("%ld",&num);

while( ch!=0)
{

ch=check(num);

// if(ch==0)
// goto l1;

switch(ch)
{
case 1:
n=num/1000;
prnt(n," thousand");
num=num-n*1000;
break;
case 2:
n=num/100;
prnt(n," hundred ");
num=num-n*100;
break;
case 3:
printf(" %s",tens[(num-20)/10]);
num=num%10;
break;
case 4:
n=num/100000;
prnt(n,"lacks");
num=num-n*100000;
break;
case 5:
n=num/10000000;
prnt(n,"crores");
num=num-n*10000000;
break;

}

}
printf(" %s",a[num-1]);
getch();
}

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1098

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