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Create a bash shell script that reads in a number from the
user. If the number is 1, print out the date. If the number
is 2, list the files in the current directory. If the number
is 3, print out who is currently logged onto the system. If
the number is anything else, print out an error message and
exit. Name this script "various.sh"
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Answer Posted / avlsubbarao
#!/bin/bash
echo "Enter Number"
read N
if [ $N == 1 ]; then
date
elif [ $N == 2 ]; then
ls
elif [ $N == 3 ]; then
who
else
echo WRONG NUMBER
fi
| Is This Answer Correct ? | 2 Yes | 2 No |
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How can we find the process name from its process id?
on “sed” command EmpData(Sample Database) 1122|j.b. saxena |g.m. |account |12/12/52|6000 2233|n.k. gupta |d.g.m |sales |31/12/40|9000 4545|anil agarwal |director |account |06/07/47|7500 5656|lalit choudhury |executive|marketing|07/09/50|5000 1265|chanchal singhvi|g.m. |admin |12/09/63|6000 0110|shyam saksena |chairman |marketing|12/12/43|8000 5566|jai sharma |director |account |23/12/89|7000 7733|jayant |d.g.m |sales |29/02/70|6000 1. From the above database substitute the delimiter of first 3 lines with “ : “ 2. From the above database substitute the delimiter with “ : ” 3. Insert the string “ XYZ Employees” in the first line. 4. Store the lines pertaining to the directors, d.g.m and g.m into three separate files. 5. Using address store first 4 lines into a file Empupdate. 6. Find the pattern “account” in the database and replaces that with “accounts”. 7. Select those lines which do not have a pattern “g.m”. 8. Insert a blank line after every line in the database.
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