write a c program to find the square of a 5 digit number
and print the result.
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Answer Posted / sarthak
I was asked to calculate the square without using long int or double. This is how i did it. I was eventually rejected but i have no idea why as the code is correct.
/*Program to find the square of a 5 digit number and print*/
#include<stdio.h>
#include<conio.h>
main()
{
clrscr();
/*Part 1: -
num is used to initially read the number
i,j are used as counters
sq is used to multiply the number with each of its digits
sq1 is used to store the result of sq with proper shift and ading zeros
result is used to store and print fial result
rem used to store remainder
quot used to store quotient
rs use as sum of coloumn*/
int num[5],i=0,j=0,sq[5][10],sq1[5][10],result[10],dig,rem,quot,rs=0;
/* Part 2: -
Reading the 5 digit number*/
printf("Enter the 5 digit number\nPlease press enter after each digit: -");
for(i=4;i>=0;i--)
{
scanf("%d",&num[i]);
}
/*Print the entered number*/
printf("\n\nYou entered the number: ");
for(i=4;i>=0;i--)
{
printf("%d",num[i]);
}
/*Part 3: -
Initialize sq as 0*/
for(i=0;i<=4;i++)
{
for(j=0;j<=9;j++)
{
sq[i][j]=0;
}
}
/*Initialize sq1 as all 0s*/
for(i=0;i<=4;i++)
{
for(j=0;j<=9;j++)
{
sq1[i][j]=0;
}
}
printf("\n\nInitially after assigning array to all 0's: -");
/*Print the 2D array after asigning it to 0*/
printf("\n\n");
for(i=0;i<=4;i++)
{
printf("\n");
for(j=0;j<=9;j++)
{
printf("%d",sq[i][j]);
}
}
/* Part 4: -
Multiply the 5 digit number with each of its own digits and storing rowise*/
for(j=0;j<=4;j++)
{
for(i=0;i<=4;i++)
{
dig=num[i]*num[j];
rem=dig%10;
quot=dig/10;
sq[i][j]=sq[i][j]+rem;
if(sq[i][j]>=10)
{
sq[i][j+1]=sq[i][j+1]+(sq[i][j]/10);
sq[i][j]=sq[i][j]%10;
}
sq[i][j+1]=sq[i][j+1]+quot;
}
}
printf("\n\nAfter multiplying the number with each of its respective digits and storing in respective rows: -");
/*Print the array without shifting*/
printf("\n\n");
for(i=0;i<=4;i++)
{
printf("\n");
for(j=0;j<=9;j++)
{
printf("%d",sq[i][j]);
}
}
/*Part 5: -
Applying shift to the array*/
for(i=0;i<=4;i++)
{
for(j=9;j>=0;j--)
{
sq1[i][j+i]=sq[i][j];
}
}
printf("\n\nAfter applying proper shift to the rows of the array: -");
/*Print after applying shift to the array*/
printf("\n\n");
for(i=0;i<=4;i++)
{
printf("\n");
for(j=0;j<=9;j++)
{
printf("%d",sq1[i][j]);
}
}
/* Part 6: -
Initialize result to 0*/
for(i=0;i<=9;i++)
{
result[i]=0;
}
/*add up the coloumns*/
quot=0;
rem=0;
for(j=0;j<=9;j++)
{
for(i=0;i<=4;i++)
{
rs=rs+sq1[i][j];
}
quot=rs/10;
rem=rs%10;
result[j]=result[j]+rem;
rs=quot;
}
printf("\n\nAfter adding up the respective coloumns of the above array \n and reversing the order: -");
/*print the result*/
printf("\n\nThe square of the numer is :- ");
for(i=9;i>=0;i--)
{
printf("%d",result[i]);
}
return 0;
}
| Is This Answer Correct ? | 2 Yes | 11 No |
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