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There are two candles of equal lengths and of different
thickness. The thicker one lasts of six hours. The thinner
2 hours less than the thicker one. Ramesh lights the two
candles at the same time. When he went to bed he saw the
thicker one is twice the length of the thinner one. How
long ago did Ramesh light the two candles .
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Answer Posted / pappu kumar yadav
Let the length of both the candles be"l".By the qstn in 6
hrs thicker candle consumes "l" length.Hence in "t" time it
consumes"(l/6)t".(where "t" s d duration during whch bth d
candles glow n chkd).Similarly during"t" time thinner
candle consumes"(l/4)t".This implies that after "t" time
length of thicker candle remaining =l-(lt/6).Length of
thinner candle remaining=l-(lt/4).Now by the question we
have (1/2)*[l-(lt/6)]=l-(lt/4). on solving this we get t=3
Hours. Hence bth d candles were lit 3 hours before.
| Is This Answer Correct ? | 23 Yes | 7 No |
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