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Write the following function in C.
stripos — Find position of first occurrence of a case-
insensitive string
int stripos ( char* haystack, char* needle, int offset )
Returns the numeric position of the first occurrence of
needle in the
haystack string. Note that the needle may be a string of
one or more
characters. If needle is not found, stripos() will return -
1.
The function should not make use of any C library function
calls.
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Answer Posted / amaresh
#include<stdio.h>
int stripos(char* haystack, char* needle, int offset );
void main()
{
char *a1, *a2;
int iPostn = 0;
printf("ENTER THE HAYSTACK STRING:\n");
gets(a1);
printf("\nENTER THE STRING - TO BE SEARCHED\n");
gets(a2);
iPostn = stripos(a1, a2, iPostn);
if(iPostn > 0)
printf("\nSTRING STARTS AT THE POSITION:
%d\n", iPostn);
else
printf("\nSTRING NOT FOUND: %d\n", iPostn);
printf("\n");
}
int is_match(char a, char b)
{
char c1, c2;
if( a >= 'A' && a <= 'Z')
c1 = a + 32;
else
c1 = a;
if( b >= 'A' && b <= 'Z')
c2 = b + 32;
else
c2 = b;
if(c1 == c2)
return 1;
else
return 0;
}
int stripos( char* haystack, char* needle, int offset )
{
int i = 0, j = 0, pos = -1;
if(*haystack == '\0' || *needle == '\0')
return -1;
while(haystack[i + j] != '\0')
{
if(is_match(haystack[i + j],needle[j]))
{
pos = i + 1;
j++;
}
else
{
i++;
pos = -1;
j = 0;
}
if(needle[j] == '\0')
return pos;
}
return -1;
}
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