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how many bytes does s9(7)COMP-3 field occupies?
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Answer Posted / vijayamala
s9(7)comp3
n=7 , (n+1)/2 = (7+1)/2 = 4.
4 bytes will be allocated for this numeric data item.
since comp3 is a packed decimal representation, each byte
can hold 2 data items. which means it 4 bytes can occupy 8
items. In which last item is left for sign digit. So
s9(4)comp3 will have 4bytes allocated & can hold 7 data
item and 1 sign digit in it.
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