4 thieves rob a bakery of the breadone after the other.each
thief takes half of what is present ,& half a bread...if
at the end 3 bread remains,what is the no of bread that
was present initially?
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Answer Posted / surya teja challapalli
Mr.Ramki,
Assume,total no of breads,x=48
first person stole,x/2 = 48/2 = 24.
second person stole,x/4 =(x/2)/2 = 24/12 =12.
third person stole, x/8 = (x/4)/2 = 12/2 =6.
fourth person stole, x/16 = (x/8)/2 = 6/2 =3.
Total breads stolen= 24+12+6+3 =45.
Still at the end there are 3 breads remaining what has
mentioned in the given question.
Hence no of breads initially are,48.
If we assume no of breads initially,x=63.
first person=31
second person=15
third person=7
fourth person=3
Breads stolen=31+15+7+3=56
Remaining breads=63-56=7
But in the question at the end there must be 3 breads
remaining,but in your logic 7 breads remaining,so 63 is
wrong one.
| Is This Answer Correct ? | 25 Yes | 9 No |
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