Answer Posted / golak bihari naik

For 3-Ph system
KVA(Apparent Power)=1.732*V*I
I=(KVA/1.732*V)*1000
I=(1/1.732*440)*1000
=1.31 A

For a 1-Ph system

KVA=V*I
I=(1/440)*1000
=2.27 A

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