In the below code, how do you modify the value 'a' and print
in the function. You'll be allowed to add code only inside
the called function.
main()
{
int a=5;
function(); // no parameters should be passed
}
function()
{
/* add code here to modify the value of and print here */
}
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Answer Posted / aravind
#include<stdio.h>
void function(void );
int main()
{
int a=5;
function();
}
function()
{
int a=4;
printf("%d",a); /* a here is a local variable*/
}
| Is This Answer Correct ? | 0 Yes | 1 No |
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A banker has a seif with a cipher. Not to forget the cipher, he wants to write it coded as following: each digit to be replaced with the difference of 9 with the current digit. The banker chose a cipher. Decipher it knowing the cipher starts with a digit different than 9. I need to write a program that takes the cipher from the keyboard and prints the new cipher. I thought of the following: Take the input from the keyboard and put it into a string or an array. Go through the object with a for and for each digit other than the first, substract it from 9 and add it to another variable. Print the new variable. Theoretically I thought of it but I don't know much C. Could you give me any kind of hint, whether I am on the right track or not?
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