a partical throw a 30 meter hieght after 2 sec another
particle thwough same velocity & mass . what is the place
they are meet each other in space.
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Answer Posted / umberto
If the particle reaches h=30m height, it has an intial speed
vo=sqrt(2*g*h) where g=9.81m/s^2 without considering air
friction. thus v0=24.3m/s. two particles will be at the same
height when y1=y2, with y the height over time of each
particle. thus: y1=v0*t-1/2*g*t^2=v0*(t-2)-1/2*g*(t-2)^2.
You can thus find the instant t at which the two particles
have the same height, which measures y1=v0*t-1/2*g*t^2
| Is This Answer Correct ? | 3 Yes | 2 No |
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