What will be the output-
for(i=1;i<=3;i++)
{
printf("%d",i);
continue;
i++;
}
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Answer Posted / harshit
This will result in compiler error as the code i++; inside
the for loop is not reachable.
If continue statement is enclosed within an if construct
then only the program will compile.
| Is This Answer Correct ? | 14 Yes | 13 No |
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