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This is related to threads. I have a class with synchronized
method m1(). Can I create different instances of this class
and execute the m1() for different threads?
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Answer Posted / qim2010
Putting code inside a synchronized block makes the compiler
append instructions to acquire the lock on the specified
object before executing the code, and release it afterwards
(either because the code finishes normally or abnormally).
Between acquiring the lock and releasing it, a thread is
said to "own" the lock. At the point of Thread A wanting to
acquire the lock, if Thread B already owns the it, then
Thread A must wait for Thread B to release it. Thus in the
example below, simultaneous calls to increment() and
getCount() will always behave as expected; a read could not
"step in" while another thread was in the middle of
incrementing.
public class Counter {
private int count = 0;
public void increment() {
synchronized (this) {
count++;
}
}
public int getCount() {
synchronized (this) {
return count;
}
}
}
| Is This Answer Correct ? | 0 Yes | 0 No |
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