Answer Posted / rahul shandilya

both of the solutions above given have complexity O(N^2),
i have tried to solve it in O(N).let me inform if there is
any bug or better solution .

#include<iostream>
using namespace std;
int main()
{
int a[130],a1[130];
memset(a,0,sizeof(a));
memset(a1,0,sizeof(a));
char ans[1000];
char str[]="putanystringhere";
for(int i=0;i<sizeof(str)/sizeof(char)-1;i++)
{
a[(int)str[i]]+=1;
}
cout<<"Enter any string of length
"<<sizeof(str)/sizeof(char)-1<<" :";
cin>> ans;
for(int i=0;i<sizeof(str)/sizeof(char)-1;i++)
{
a1[(int)ans[i]]+=1;
}
bool flag=true;
for(int i=0;i<sizeof(str)/sizeof(char)-1;i++)
{
if(a[(int)str[i]]!=a1[(int)str[i]])
{
flag=false;
break;
}
}
if(flag==true)
cout<<"No error";
else
cout<<"Error";
system("pause");
return 0;
}

#include int main(void) { int a=4, b=2; a=b<>2 ; printf("%d",a); return 0; }

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