How to initialize 20,000 bytes in the Assembler..
- 5 Answers
- 16336 Views
- Amdocs, IBM, I also Faced
- E-Mail Answers
Answer Posted / roocarlin
since the machine-code for MVC moves up to 256 bytes, you would need to do a series of MVCs to initialize 20000 bytes. this requires that you maintain a register or two to keep track of how far you've progressed through initialization.
possibly, you could get MVCL to do it; i've never tried...
MVCL uses 2 sets of even-odd pairs of registers to do the move.
you specify source address, destination address, length of source, length of destination, and fill character in the registers. the fill-character goes into the high order byte of (I THINK...) the destination length register (in this case r4)
l r4,=f'20000'
l r6,=f'20000'
la r7,source_field
la r5,dest_field
mvcl r4,r6
| Is This Answer Correct ? | 10 Yes | 3 No |
Post New Answer View All Answers
Explain the difference between various read and find statement?
What does the following code do? Ap wkur,=p5 where wkur is a label?
Explain about maximum displacement?
How is data passed from a calling program to an assembler called program?
explain icm instruction?
How do you round the addition or subtraction of two numbers in assembler?
Explain the difference between various read and find statement and which one should be used when for better adabas performance?
What is maximum displacement and how to cross this limit?
Ap wkur,=p5 where wkur is a label?
What is need of start 0? In steed of can we use anyother numerics? If we use what will happen?
explain about maximum displacement and how to cross this limit?
Explain how to pass instream data in sysin with assembler?
Explain how to initialize a register to 0000?
What will happen if we drop the base register in the program which contains only one basereg?
What is icm instruction?
