Answer Posted / ashutosh tiwari

int find_num(int *arr, int *arr_num, int arr_size)
{
int i;
while((i<arr_size) && (*(arr+i) != *arr_num))
i++;
if(i >= arr_size)
return -1;
else
return i;
}

OR

int find_num(int *arr, int *arr_num, int arr_size)
{
int i;
for(i=0;i<arr_size;i++)
{
if(*(arr+i) != *arr_num)
continue;
else
return i;
}
return -1;
}

input to function will be actual array, number to be found
with its reference and array size
output will be -1 if fail otherwise number position

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