Study the code:
void show()
main()
{
show();
}
void show (char *s)
{
printf("%sn",s);
}
What will happen if it is compiled & run on an ANSI C
Compiler?
A)It will compile & nothing will be printed when it is
executed
B)it will compile but not link
C)the compiler will generate an error
D)the compiler will generate a warning
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Answer Posted / manjeet
The compiler will generate an error because the is no ";"
semicolon after the prototype declaration of show function
| Is This Answer Correct ? | 2 Yes | 0 No |
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