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There are 9 coins. Out of which one is odd one i.e weight
is less or more. How many iterations of weighing are
required to find odd coin?
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Answer Posted / sabarish
ans ) 2 iterations
arrange 9 coins into 3 batches each of 3.
first weigh : weigh 2 batches and find the defective. if
the balance shows no movement then the 3rd batch is under
defect.
second weigh : from this batch , take any 2 balls out out
of 3, and weigh it.if there is movement in balance then
defective ball is found. if not , then the 3rd ball tht is
outside is the defective.
| Is This Answer Correct ? | 76 Yes | 53 No |
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