Answer Posted / soruabh
When you call a function your compiler enters a
call-sequence (which takes
time) and allocates a new stack frame for that function
(whcih takes text
stack space) so that the function's body can be executed.
After it's done
you enter a returning-sequence phase (which takes time).
A macro does not need anything of the above, because it's
preprocessor's job
to expand a macro, it's only about text replacement, not
about compiler
stuff or code-generating issues. So you don't expend time
and space doing
what a function would need in order to be executed.
| Is This Answer Correct ? | 4 Yes | 0 No |
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