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Answer Posted / rithesh
I/P converter - all the instrument calibration principal
will be same. In beanch calibration we have to give
pnumatic input of instrument air/ nitrogen with pressure of
1.4 bar or kg/cm2 or 21 psi and we have to fix a test gauge
of 0 to 1.5 bar(kg/cm2)/ 0 to 20psi at pnumatic output. now
we have to connect mA source to I/P converter. we have vary
the mA 4 to 20. the result will be like this.
input 4mA output will be 0.2 bar(kg/cm2) / 3 psi
input 8mA output will be 0.4 bar(kg/cm2) / 6 psi
input 12mA output will be 0.6 bar(kg/cm2) / 9 psi
input 16mA output will be 0.8 bar(kg/cm2) / 12 psi
input 20mA output will be 1 bar(kg/cm2) / 15 psi
if output not match with input we have to set things by
adjesting Zero and Span adjesting point.
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Q1: Consider part of a control loop, which excludes the transmitter, consisting of a process, a controller and a control valve which may be represented by two dead times of 0.5 min each and three exponential lags of 0.8 min., 1.0 min. and 1.5 min. respectively. We wish to express this system as an overall first order plus dead time (FOPLD) model ie gain, time constant and process dead time. (We will see later that this is often done, to simplify controller tuning). For this exercise, gain is considered to be 1.0. (A) If the transmitter is a flow transmitter whose behaviour can be described by a dead time of 0.2 min. and an exponential lag of 0.5 min. in terms of the overall dead time and overall first order lag how can the system behaviour be approximated ? Overall dead time = Overall time constant = (B) If the transmitter is a temperature transmitter with a temperature sensor in a protecting well whose behaviour can be described by a dead time of 0.7 min. and an exponential lag of 15 min. how can the overall system behaviour be approximated now? Overall dead time = Overall time constant =
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