void main()
{
int i=1;
printf("%d%d%d",i,++i,i++);
}
Cau u say the output....?
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Answer Posted / tommy tom
331
Since printf can't know how many operands will be passed in, and since it was made during a time of limited computing resources, the operands are pushed onto a stack, and evaluated after being popped off, thus they are evaluated in LIFO order, or right to left.
i++ is printed as 1, then incremented.
++i is incremented then printed as 3
i = 3.
Reassembling in the order as passed into the function then, 331
There are no spaces or line returns in the format string either, so after the run, the terminal prompt will be tacked directly onto the end of the program's output.
| Is This Answer Correct ? | 10 Yes | 4 No |
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