main()
{ int i;
printf("%d",((i=1)*i-- - --i*(i=-3)*i++ + ++i));
}
ans is 24 bt how?pls tell smbody............
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Answer Posted / gorgeousgirl
Answer: 34
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Explanation:
by order of precedence, parenthesis hav highest priority
so
(i=1)*i-- - --i*(i=-3)*i++ + ++i
i=1 i=-3
now, i=-3
after assignment operations the expr becomes,
>(i)*i-- - --i*(i)*i++ + ++i
next higher priority is for auto-in/decrement
omitting post in/decrement(as they hav effect only after
this line of code), we get,
> i*i - --i*i*i + ++i
the associativity for printf statement is from right to left
so ++i is executed first before --i where i=-3
> i*i - --i*i*i + -2
now i=-2
> i*i - -3*i*i + -2
now i =-3
next precedence is for multiplication
> -3*-3
-
-3*-3*-3
+
-2
> 9 - -27 + -2
> 9 + 27 -2
> 9 + 25
> 34
| Is This Answer Correct ? | 3 Yes | 0 No |
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