Answer Posted / rama krishna sidhartha

Here are some examples for getch() and getche() to distinguish :

Example for getch() :

main()
{
getch();
}
OUTPUT : black screen(nothing is displayed)

Example for getche() :

main()
{
getche();
}
OUTPUT : u(the cursor waits for sometime untill you press
any key from the keyboard after pressing it immediately goes
to blue screen)

Write a program to identify if a given binary tree is balanced or not.

1094

---

we called a function and passed something do it we have always passed the "values" of variables to the called function. such functions calles are called a) calls by reference b) calls by value c) calls by zero d) none of the above

1106

---

Explain the red-black trees?

1055

---

find the sum of two matrices and WAP for it.

1071

---

What does == mean in texting?

1216

---

Explain how do you list a file’s date and time?

990

---

What is storage class?

1019

---

Explain what is dynamic data structure?

1118

---

I need help with the following lab. Can anyone explain it to me on how to approach this problem. Coding would be great too !!! No busy waiting allowed. Remember that Java monitors are 'signal and continue'. The input data is called the database (DB). In this problem, it consists of a single variable initialized in the main thread, to contain the current time of day in HH:MM:SS:mmm format (mmm is milliseconds) truncated to 3 digits. Threads follow these rules: 1. Readers may all attempt to read at the same time, but NOT if a writer is writing (i.e.; the writer is in the monitor. 2. Writing is exclusive (only 1 writer at a time, no readers while writing). 3. Options: (to be specified by instructor) a. Readers have absolute priority over writers. b. Writers have absolute priority over readers c. When a reader arrives and a writer is waiting, the reader is suspended behind the writer instead of being admitted immediately. Thus, a writer waits for readers that were running when it arrived, but does not to wait for new readers. You may program this in C++ or Java. There are 4 controlling input values: 1. r – number of readers 2. w – number of writers 3. R – delay for a reader to restart 4. W – delay for a writer to restart Create the following program consisting of 1 main process (your main program) with n threads: 1. The main thread: a. Creates the 'n' threads needed. Of these, r of them are readers and w of them are writers. Starts all readers and writers. b. Waits for all 'n' threads to complete. You may use any method to detect when they are all complete. c. Prints out the resulting outputs from the threads. 2. Threads: a. When a thread starts to run, it immediately tries to enter the monitor. b. A reader thread reads the DB, outputs the exact message below, then exits: >>> DB value read =: HH:MM:SS:mmm by reader number: rr where the underlined text is replaced with actual data. c. A writer thread updates the DB with a new value (from the system time), outputs the exact message below, then exits: *** DB value set to: HH:MM:SS:mmm by writer number: ww where the underlined text is replaced with actual data. d. Each thread accesses the data a total of 10 times, exiting, then re-entering the monitor after each access. Hints: 1. File access *might* not be thread-safe, so you should be prepared to handle this. Read the documentation for the language you are using. 2. Suggested values for delays are: a. If looping, R >=1,000,000 and W>=100,000 b. If using “sleep”, then R=100 ms, W=50 ms. Additional: • Thread output is to ONE file used by ALL threads (so you need to synchronize access to it). • Readers must provide sufficient delay that results are useful (delay by R before re-trying). R is another input value. • Writers must also delay. Delay by W, updating the DB each time. W is an input. • Test your program with AT LEAST TWO different sets of values for r and w (#s of readers and writers) plus this set: r = 4, w=2. Basic operation of a thread: attempt to enter the monitor. If unsuccessful, you get put on a queue. When you get in, read or write the data (depending on type of thread), exit the monitor, wait the required delay amount, then try again. Repeat 10 times.

1907

---

Suppose we have a table name EMP as below. We want to perform a operation in which, I want to change name ‘SMITH’ from as ‘SMITH JAIN’. Also I want to change the name of the column from ENAME to E_NAME. EMPNO ENAME JOB MGR HIREDATE SAL 7369 SMITH Coder 7902 17-DEC-80 800 7499 ALLEN SALESMAN 7698 20-FEB-81 1600 7521 WARD SALESMAN 7698 22-FEB-81 1250

1919

---

in multiple branching construct "default" case is a) optional b) compulsarily c) it is not include in this construct d) none of the above

1017

---

please help me..... please codes and flowchart plz turbo c lang po yan.....please asap response... 3. Make an astrology program. The user types in his or her birthday (month, day, and year as integer), and the program responds with the user’s zodiac sign, horoscope, and other information related to it. If the user’s birth year falls into a leap year, your program should display an appropriate message for it. NOTES: Conditional Statements: it should be with graphics

3276

---

What is the c language function prototype?

1044

---

What is || operator and how does it function in a program?

1043

---

Why do we use null pointer?

999

---