main()
{
int i=5;
printf("%d%d%d%d",i++,i--,i);
}
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Answer Posted / sravankumar
printf() function evaluates from right to left
printf("\n %d %d %d",i++,i--,i);
4 5 5
<- <- <- <- <-evaluation of expression
but prints as the way we mentioned in printf() function
i.e first i = 5
then i--= 5 because it is post decrement
then i++= 4 this because i is decremented in above, and
not incremented immediately because is post
increment
So output is : 4 5 5
| Is This Answer Correct ? | 0 Yes | 3 No |
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