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a watch which looses uniformly was observed to be 12 min
fat at 4am.on 6th of a month.it showed 20 min less than
thae correct time at 6pm on the 10th of the same month.when
did the watch show correct time
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Answer Posted / ramesh ps
1. Watch was observed +12 minutes at 4 am on 6th of the
month
2. Watch was observed -20 minutes at 6 pm on 10th of the
month
The watch ad lost 32 minutes in n number of hours
Number of hours between these intervals = 20+24+24+24+18=110
Since watch is slowed down by 32 minutes (from +12 to -20)
in 110 hours
Number of hours took to slowed down one minute = 110/32
Number of hours took to slowdown 12 minutes at which the
watch was showing correct time is = (110/32)*12 = 41.25
If I add 41.25 to 4 Am of 6th Of the month then it will
become 11:25 PM on 7th of the month.
| Is This Answer Correct ? | 3 Yes | 6 No |
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