Answer Posted / sumankumar

IT MEANS DATA SPLIT INTO 2 HALFS AND COMPARE FIRST HALF LAST
VALUE AND SECOND HALF FIRST VALUE WITH GIVEN DATA THEN
ELIMINATE HALF OF THE DATA AND AGAIN SPLIT INTO NEXT 2 HALFS
THIS PROCCESS WILL BE CONTINUED STILL VALUE IS IDENTIFIED

LET ME KNOW ONE EX:
PROGRAM: CONSIDER 1,2,3,4,5,6,7,8,9,10.
SET I TO 2
SEARCH ALL DATA
AT END DISPLY " EOT"
WHEN DATA(I)= 4
END-SEARCH ALL

SOL: THE DATA DIVIDE INTO 2 HALFS 1 TO 4, 5 TO 10 U R
REQUIREMENT IS SERCH AT POSITION OF 4 SO IT COMPARE FIRST
HALFS OF LAST VALUE i'e 4 AND SECOND HALFS OF FIRST VALUE
i'e 5 AND ELIMINATE THE HALF OF DATA AND AGAIN SPLIT IT INTO
NEXET 2 HALFS THIS PROCCESS WILL BE CONTINUED STILL VALUE IS
IDENTIFIED

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