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01 x pic s9(8) comp.
How will the following value be internally allocated
'18787'

Question Posted / kapil arya

Answer Posted / kapil arya

Basically Comp Makes the word boundary.
(0 - 4) 2 Bytes (Half Word boundary)
(5-9) 4 Bytes (Full Word Boundary)
(10-18) 8 byte Double word Boundary

Because it is s9(8) Comp..
So I will take 4 byte to store the date.
And it will allocated like:
01 87 87 , will store in 3 byte and one byte will be free
or unused..



Guys or Girls i have one question...
Related to JCL
I have a jcl where in a step i have one DD statement where
i am concatinating the 3 dataset..so in next step i want to
override the 3rd dataset only.. So how can i override the
3rd dataset.. Please let me know the answer...
Thanks to All..

Is This Answer Correct ?    9 Yes 0 No



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