Answer Posted / adil naseem(pakistan)

cos(pi1)=0.92 //old power factor
cos(pi2)=0.98 //desired power factor
the forlmula for saving of Kw is:
total Kw= 350kw



Saving KW = total kw * (tan(pi1) - tan(pi2))
=350 * (0.4259 - 0.203058)
=77.9947Kw is the answer!(100% correct)

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