Answer Posted / pavan mustyala

#include<iostream>
using namespace std;

void main()
{
char *arr1[9]=
{"one","two","three","four","five","six","seven","eight","ni
ne"};
char *arr2[8]=
{"twenty","thirty","fourty","fifty","sixty","seventy","eight
y","ninety"};
int num;

cout << "Enter A Number:"<< endl;
cin >> num;

cout << arr2[(num / 10) - 2];

if((num % 10) != 0)
cout << " " << arr1[(num % 10) -1];
}

U hv to enter a range from a and b and search hw many no. of times a pattern n. occurs between the range a and b. Eg :i/p:enter range :0 100 Enter pattern: 13 o/p: the no. times 13 occurred betwwn 0 to 100:1 Eg :i/p:enter range :100 1000 Enter pattern: 13 o/p: the no. times 13 occurred betwwn 100 to 1000: (in this 13,113,131,132,133…139,213,313,…913 all these will be counted)

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Given a table of the form: Product Sold on A 1/1/1980 B 1/1/1980 C 1/1/1980 A 1/1/1980 B 1/1/1980 C 2/1/1980 A 2/1/1980 There are 30 products and 10,000 records of such type. Also the month period during which sales happened is given to u. Write the program to display the result as: Product Month No. of copies A January 12 A February 15 A March 27 B January 54 B February 15 B March 10 C January 37

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