Answer Posted / ravi

Assuming we start with Level 1, (in Java)

{{{

public class BinaryTreeSearch {

/**
* @param args
*/
public static void main(String[] args) {

BinaryTreeSearch test = new BinaryTreeSearch();
Node root = test.new Node(null, null, "Value");
Node last = root;
Node middle = null;
for (int i = 0; i < 10; i++) {
Node temp = test.new Node(null, null, "Value");
last.setLeft(temp);
last = temp;
if (i == 5)
middle = temp;
}
for (int i = 0; i < 20; i++) {
Node temp = test.new Node(null, null, "Value");
middle.setRight(temp);
middle = temp;
}

for (int i = 0; i < 10; i++) {
Node temp = test.new Node(null, null, "Value");
last.setRight(temp);
last = temp;
}

int depth = depth(root, 0);
System.out.println(depth);
}

private static int depth(Node node, int level) {
if (null == node)
return level;
level++;
int leftLevel = depth(node.getLeft(), level);
int rightLevel = depth(node.getRight(), level);

if (leftLevel > rightLevel) {
return leftLevel;
} else {
return rightLevel;
}
}

public class Node {
Node left = null;
Node right = null;
String strValue = null;

public Node(Node left, Node right, String value) {
this.left = left;
this.right = right;
this.strValue = value;
}

public void setLeft(Node left) {
this.left = left;
}

public void setRight(Node right) {
this.right = right;
}

public void setValue(String value) {
this.strValue = value;
}

public Node getLeft() {
return left;
}

public Node getRight() {
return right;
}
}
}

}}}

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