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int *p=20;
if u print like dis printf("%d",p);
o\p:- 20; how is it possible?
plz give me the explanation.
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Answer Posted / yogi
int *p=20;
This is like int *p;p=20;
printf("%d",p);It prints p properly as 20;
printf("%d",*p);It means deference the value at address 20,
which is invalid .
If we try to run,as address 20 is invalid and it tries to
fetch the value at address 20,signal 11 sent to that process
i.e it dumps core with segmentation fault
| Is This Answer Correct ? | 4 Yes | 0 No |
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