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There are 3 friends X,Y,Z having some chocolates each.
X Gives Y and Z as many chocolates as they already have.
After some days Y gives X and Z as many chocolates as they
have.
After some days Z gives X and Y as many chocolates as they
have.
Finally each has 24 chocolates. What is the original No. of
chocolates each had in the beginning?
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Answer Posted / anjali
solution x = 39, y = 21, z = 12
solve it by backtracking.
we know finally each has 24.
x y z
--- --- ---
final: 24 24 24
12 12 48 before z gives
6 42 24 before y gives
initial: 39 21 12 before x gives
| Is This Answer Correct ? | 54 Yes | 7 No |
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