Answer Posted / rupinder

You overload a binary unary operator with either a nonstatic
member function that has one parameter, or a nonmember
function that has two parameters. Suppose a binary operator
@ is called with the statement t @ u, where t is an object
of type T, and u is an object of type U. A nonstatic member
function that overloads this operator would have the
following form:

return_type operator@(T)

A nonmember function that overloads the same operator would
have the following form:

return_type operator@(T, U)

An overloaded binary operator may return any type.

The following example overloads the * operator:

struct X {

// member binary operator
void operator*(int) { }
};

// non-member binary operator
void operator*(X, float) { }

int main() {
X x;
int y = 10;
float z = 10;

x * y;
x * z;
}

The call x * y is interpreted as x.operator*(y). The call x
* z is interpreted as operator*(x, z).

i am getting an of the type can not convert int to int *. to overcome this problem what we should do?

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