Hi All, Can you please let me know how to grep for a
particular pattern in unix. I want to print the dates from
the file exp.txt. the date pattern is DD:MM:YYYY, I just
want to print all the dates from the file exp.txt.
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Answer Posted / mo
#1: grep '[0-9][0-9]-[0-9][0-9]-[0-9][0-9][0-9][0-9]'
<filename> | more
from #1 output see which column is returned for date.
use next this command.
#1: grep '[0-9][0-9]-[0-9][0-9]-[0-9][0-9][0-9][0-9]'
<filename> | cut -f<from the first command> -d"<Delimeter
of file>
| Is This Answer Correct ? | 2 Yes | 0 No |
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