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A normally pigmented man (dominant) marries an albino woman
(recessive). They have 3 children, one of whom is an
albino. What is the genotype of the man?
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Answer Posted / prussian embassy
To correctly answer the question, the normally pigmented
man would be "Aa": A for his dominant trait of normal
pigmentation, and "a" for the gene of albinism.
Reasons supporting this answer are this; for a recessive
trait to show itself by any means, it would need to be the
only factors in the gene. Together, they look something
like this.
A x
,-------
a |Aa |ax |
|___|___|
|Aa |ax |
a |___|___|
The genotype of the children are Aa, Aa, and aa.
For there to be a posibility of having a child albino, the
normally pigmented man must have the ressesive gene.
Therefore turning the chart above into this.
A a
,-------
a |Aa |aa |
|___|___|
|Aa |aa |
a |___|___|
In the end, it proves that the normally pigmented man's
genotype is "Aa": A for his dominant trait of normal
pigmentation, and "a" for the gene of albinism.
| Is This Answer Correct ? | 13 Yes | 1 No |
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