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what would be the output of the following program?
main()
{
int k = 123;
char *ptr;
ptr = &k;
printf("%d",*ptr);
}
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Answer Posted / vadivelt
Output would be 123.
Since, the character pointer can hold the values
0 - 255(if it is unsigned) or -128 to 127 (if it is signed), we
will get value of k as result.
But if the k value is k > 255 and the pointer is unsigned,
or if the k value is k > -129 and k < 128 and the pointer
is signed then only lower 1 byte of k would be the result.
Remaining data will be lost.
| Is This Answer Correct ? | 4 Yes | 0 No |
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