Answer Posted / vadivel t

Hi All,
The size of any data type is depends on the compiler
(including struct, union and enum). But the question does
not mean, "what is the size of the given structure".

It actually means,
Find the size of the structure without using sizeof()
operator.

The Answer, irrespective of compiler would be,

Output of the following code.

-First printf gives the size of the structure, wthout using
size of operator.

-U can cross check the ans using sizeof() operator in the
second printf().

#include<stdio.h>
struct name
{
int a;
char b;
int *p;
}abc;

main()
{
struct name *ptr, *ptr1;
ptr = &abc;
ptr1 = ptr + 1;
printf("WITHOUT USING sizeof() OPERATOR: %d \n",((char *)
ptr1 - (char *)ptr));
printf("USING sizeof() OPERATOR: %d \n", sizeof(abc));
getch();
}

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