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main()
{
char *p1="Name";
char *p2;
p2=(char *)malloc(20);
while(*p2++=*p1++);
printf("%s\n",p2);
}
what is the output?
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Answer Posted / vadivel t
In addtion to the answer #5.
printf("%s\n",p2); will print the values from 6th byte to
20th byte.
6th byte to 20th bytes of the memory will contain some
Garbage value. So the output will be a string of garbage
values.
For desired o/p see the ans #5
| Is This Answer Correct ? | 6 Yes | 3 No |
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