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Answer Posted / rck
The complier treats a[0] as *(a+0) ie *(a+0) (array name is
the base address of that array)gives the first element of
the array.
If the array starts from 1 a[1] is treated as *(a+1) gives
the second element of array.The first element is missing.so
array always starts from 0.
| Is This Answer Correct ? | 35 Yes | 14 No |
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