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1. Wrie a function which returns the most frequent number
in a list of integers. Handle the case of more than one
number which meets this criterion.
public static int[] GetFrequency(int[] list)
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Answer Posted / vadivel t
Hi,
The below code shall serve the purpose of the question but
it will work only for single digit elements. (ie., array
should contain sigle digit nos)
#include<stdio.h>
#include<conio.h>
int main()
{
int local[10] = {0,0,0,0,0,0,0,0,0,0};
int a[100];
int i, j, repeat, length, big;
int result[13];
printf("ENTER NO OF ELEMENTS IN THE ARRAY\n");
scanf("%d", &length);
printf("ENTER THE ELEMENTS IN THE ARRAY\n");
for(i = 0; i< length; i++)
{
scanf("%d", &a[i]);
}
for(i = 0; i<length; i++)
{
repeat = 0;
for(j = 0; j<length; j++)
{
if(a[j] == i)
{
repeat++;
}
}
local[i] = repeat;
//printf("%d \n", repeat);
}
big = 0;
for(i = 0; i<length; i++)
{
if(big < local[i])
{
big = local[i];
}
}
/*put the data in result buffer*/
for(i = 0, j = 0 ; i<length; i++)
{
if(local[i] == big)
{
result[++j] = i;
}
}
result[0] = j;
result[++j] = big;
printf("No(s) ");
for(i = 0; i< result[0]; i++)
{
printf("%d, ", result[i+1]);
}
printf("Repeats %d times\n", result[j]);
getch();
}
| Is This Answer Correct ? | 6 Yes | 19 No |
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