Answer Posted / vadivel t

Hi,
The below code shall serve the purpose of the question but
it will work only for single digit elements. (ie., array
should contain sigle digit nos)

#include<stdio.h>
#include<conio.h>

int main()
{
int local[10] = {0,0,0,0,0,0,0,0,0,0};
int a[100];
int i, j, repeat, length, big;
int result[13];

printf("ENTER NO OF ELEMENTS IN THE ARRAY\n");
scanf("%d", &length);
printf("ENTER THE ELEMENTS IN THE ARRAY\n");
for(i = 0; i< length; i++)
{
scanf("%d", &a[i]);
}

for(i = 0; i<length; i++)
{
repeat = 0;

for(j = 0; j<length; j++)
{
if(a[j] == i)
{
repeat++;
}
}
local[i] = repeat;
//printf("%d \n", repeat);
}

big = 0;
for(i = 0; i<length; i++)
{
if(big < local[i])
{
big = local[i];
}
}
/*put the data in result buffer*/
for(i = 0, j = 0 ; i<length; i++)
{
if(local[i] == big)
{
result[++j] = i;

}
}
result[0] = j;
result[++j] = big;

printf("No(s) ");
for(i = 0; i< result[0]; i++)
{
printf("%d, ", result[i+1]);
}
printf("Repeats %d times\n", result[j]);
getch();
}

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